(3x+12)/(x+4)=(4x^2+8x+18x^2)/(2x)

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Solution for (3x+12)/(x+4)=(4x^2+8x+18x^2)/(2x) equation: 



(3x+12)/(x+4)=(4x^2+8x+18x^2)/(2x)

We move all terms to the left:

(3x+12)/(x+4)-((4x^2+8x+18x^2)/(2x))=0



Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: (x+4)!=0

We move all terms containing x to the left, all other terms to the right

x!=-4

x∈R



We calculate fractions


(-((4x^2+8x+18x^2)*(x+4))/2x*x+(3x+12)*2x)/2x*x=0

We can not solve this equation

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